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說課稿科學三年級上冊《觀察水》
二、說教學方法。建構主義認為，科學知識不是通過教師傳授得到，而是學習者在一定 學習環(huán)境下，在教師和學生伙伴的幫助下，利用必要的學習資源，通過自已意義建構而獲得 的，在這一理論的指導下，對本課的教學設計和學法指導作如下思考：直觀教學，依據(jù)本課教學思路，聯(lián)系學生生活實際，通過分組實驗和（實物展示）讓學 生動口、動手、動眼、動腦，充分重視學生的直接經(jīng)驗，感受獲得。情境教學從兒童身邊自然事物，生活中關于水一些有趣的現(xiàn)象，開始探究活動，利用一 些必要的工具，營造科學探究的學習情境，倡導讓學生經(jīng)歷科學探究拓學習活動，在探究中 培養(yǎng)他們的好奇心和探究欲。
圓的一般方程教學設計人教A版高中數(shù)學選擇性必修第一冊
情境導學前面我們已討論了圓的標準方程為(x-a)2+(y-b)2=r2,現(xiàn)將其展開可得：x2+y2-2ax-2bx+a2+b2-r2=0.可見,任何一個圓的方程都可以變形x2+y2+Dx+Ey+F=0的形式.請大家思考一下,形如x2+y2+Dx+Ey+F=0的方程表示的曲線是不是圓?下面我們來探討這一方面的問題.探究新知例如,對于方程x^2+y^2-2x-4y+6=0,對其進行配方，得〖(x-1)〗^2+(〖y-2)〗^2=-1,因為任意一點的坐標 (x,y) 都不滿足這個方程，所以這個方程不表示任何圖形，所以形如x2+y2+Dx+Ey+F=0的方程不一定能通過恒等變換為圓的標準方程，這表明形如x2+y2+Dx+Ey+F=0的方程不一定是圓的方程.一、圓的一般方程（1）當D2+E2-4F>0時,方程x2+y2+Dx+Ey+F=0表示以(-D/2,-E/2)為圓心,1/2 √(D^2+E^2 "-" 4F)為半徑的圓,將方程x2+y2+Dx+Ey+F=0，配方可得〖(x+D/2)〗^2+(〖y+E/2)〗^2=(D^2+E^2-4F)/4（2）當D2+E2-4F=0時,方程x2+y2+Dx+Ey+F=0，表示一個點(-D/2,-E/2)（3）當D2+E2-4F0);
直線的一般式方程教學設計人教A版高中數(shù)學選擇性必修第一冊
解析:當a0時,直線ax-by=1在x軸上的截距1/a0,在y軸上的截距-1/a>0.只有B滿足.故選B.答案:B 3．過點(1,0)且與直線x－2y－2＝0平行的直線方程是( ) A．x－2y－1＝0 B．x－2y＋1＝0C．2x＋y＝2＝0 D．x＋2y－1＝0答案A 解析：設所求直線方程為x－2y＋c＝0，把點(1,0)代入可求得c＝－1.所以所求直線方程為x－2y－1＝0.故選A.4．已知兩條直線y＝ax－2和3x－(a＋2)y＋1＝0互相平行，則a＝________.答案：1或－3 解析：依題意得：a(a＋2)＝3×1，解得a＝1或a＝－3.5．若方程(m2－3m＋2)x＋(m－2)y－2m＋5＝0表示直線．(1)求實數(shù)m的范圍；(2)若該直線的斜率k＝1，求實數(shù)m的值．解析： (1)由m2－3m＋2＝0，m－2＝0，解得m＝2，若方程表示直線，則m2－3m＋2與m－2不能同時為0，故m≠2.(2)由－?m2－3m＋2?m－2＝1，解得m＝0.
點到直線的距離公式教學設計人教A版高中數(shù)學選擇性必修第一冊
4.已知△ABC三個頂點坐標A(－1,3)，B(－3,0)，C(1,2)，求△ABC的面積S.【解析】由直線方程的兩點式得直線BC的方程為 ＝ ，即x－2y＋3＝0，由兩點間距離公式得|BC|＝ ，點A到BC的距離為d，即為BC邊上的高，d＝ ，所以S＝ |BC|·d＝ ×2 × ＝4，即△ABC的面積為4.5.已知直線l經(jīng)過點P(0,2),且A(1,1),B(-3,1)兩點到直線l的距離相等,求直線l的方程.解:(方法一)∵點A(1,1)與B(-3,1)到y(tǒng)軸的距離不相等,∴直線l的斜率存在,設為k.又直線l在y軸上的截距為2,則直線l的方程為y=kx+2,即kx-y+2=0.由點A(1,1)與B(-3,1)到直線l的距離相等,∴直線l的方程是y=2或x-y+2=0.得("|" k"-" 1+2"|" )/√(k^2+1)=("|-" 3k"-" 1+2"|" )/√(k^2+1),解得k=0或k=1.(方法二)當直線l過線段AB的中點時,A,B兩點到直線l的距離相等.∵AB的中點是(-1,1),又直線l過點P(0,2),∴直線l的方程是x-y+2=0.當直線l∥AB時,A,B兩點到直線l的距離相等.∵直線AB的斜率為0,∴直線l的斜率為0,∴直線l的方程為y=2.綜上所述,滿足條件的直線l的方程是x-y+2=0或y=2.
兩點間的距離公式教學設計人教A版高中數(shù)學選擇性必修第一冊
一、情境導學在一條筆直的公路同側有兩個大型小區(qū),現(xiàn)在計劃在公路上某處建一個公交站點C,以方便居住在兩個小區(qū)住戶的出行.如何選址能使站點到兩個小區(qū)的距離之和最小?二、探究新知問題1.在數(shù)軸上已知兩點A、B，如何求A、B兩點間的距離？提示：|AB|＝|xA－xB|.問題2：在平面直角坐標系中能否利用數(shù)軸上兩點間的距離求出任意兩點間距離？探究.當x1≠x2，y1≠y2時，|P1P2|＝？請簡單說明理由．提示：可以，構造直角三角形利用勾股定理求解．答案：如圖，在Rt △P1QP2中，|P1P2|2＝|P1Q|2＋|QP2|2，所以|P1P2|＝?x2－x1?2＋?y2－y1?2.即兩點P1(x1，y1)，P2(x2，y2)間的距離|P1P2|＝?x2－x1?2＋?y2－y1?2.你還能用其它方法證明這個公式嗎？2．兩點間距離公式的理解(1)此公式與兩點的先后順序無關，也就是說公式也可寫成|P1P2|＝?x2－x1?2＋?y2－y1?2.(2)當直線P1P2平行于x軸時，|P1P2|＝|x2－x1|.當直線P1P2平行于y軸時，|P1P2|＝|y2－y1|.
傾斜角與斜率教學設計人教A版高中數(shù)學選擇性必修第一冊
(2)l的傾斜角為90°,即l平行于y軸,所以m+1=2m,得m=1.延伸探究1 本例條件不變,試求直線l的傾斜角為銳角時實數(shù)m的取值范圍.解:由題意知(m"-" 1"-" 1)/(m+1"-" 2m)>0,解得1<m<2.延伸探究2 若將本例中的“N(2m,1)”改為“N(3m,2m)”,其他條件不變,結果如何?解:(1)由題意知(m"-" 1"-" 2m)/(m+1"-" 3m)=1,解得m=2.(2)由題意知m+1=3m,解得m=1/2.直線斜率的計算方法(1)判斷兩點的橫坐標是否相等,若相等,則直線的斜率不存在.(2)若兩點的橫坐標不相等,則可以用斜率公式k=(y_2 "-" y_1)/(x_2 "-" x_1 )(其中x1≠x2)進行計算.金題典例 光線從點A(2,1)射到y(tǒng)軸上的點Q,經(jīng)y軸反射后過點B(4,3),試求點Q的坐標及入射光線的斜率.解:(方法1)設Q(0,y),則由題意得kQA=-kQB.∵kQA=(1"-" y)/2,kQB=(3"-" y)/4,∴(1"-" y)/2=-(3"-" y)/4.解得y=5/3,即點Q的坐標為 0,5/3 ,∴k入=kQA=(1"-" y)/2=-1/3.(方法2)設Q(0,y),如圖,點B(4,3)關于y軸的對稱點為B'(-4,3), kAB'=(1"-" 3)/(2+4)=-1/3,由題意得,A、Q、B'三點共線.從而入射光線的斜率為kAQ=kAB'=-1/3.所以,有(1"-" y)/2=(1"-" 3)/(2+4),解得y=5/3,點Q的坐標為(0,5/3).
兩條平行線間的距離教學設計人教A版高中數(shù)學選擇性必修第一冊
一、情境導學前面我們已經(jīng)得到了兩點間的距離公式，點到直線的距離公式，關于平面上的距離問題，兩條直線間的距離也是值得研究的。思考1：立定跳遠測量的什么距離？A.兩平行線的距離 B.點到直線的距離 C. 點到點的距離二、探究新知思考2：已知兩條平行直線l_1,l_2的方程，如何求l_1 〖與l〗_2間的距離？根據(jù)兩條平行直線間距離的含義，在直線l_1上取任一點P（x_0,y_0 ），,點P（x_0,y_0 ）到直線l_2的距離就是直線l_1與直線l_2間的距離，這樣求兩條平行線間的距離就轉化為求點到直線的距離。兩條平行直線間的距離1. 定義：夾在兩平行線間的__________的長.公垂線段2. 圖示： 3. 求法：轉化為點到直線的距離.1．原點到直線x＋2y－5＝0的距離是( )A．2 B．3 C．2 D．5D [d＝|－5|12＋22＝5.選D.]
兩直線的交點坐標教學設計人教A版高中數(shù)學選擇性必修第一冊
1.直線2x+y+8=0和直線x+y-1=0的交點坐標是( )A.(-9,-10) B.(-9,10) C.(9,10) D.(9,-10)解析:解方程組{■(2x+y+8=0"," @x+y"-" 1=0"," )┤得{■(x="-" 9"," @y=10"," )┤即交點坐標是(-9,10).答案:B 2.直線2x+3y-k=0和直線x-ky+12=0的交點在x軸上,則k的值為( )A.-24 B.24 C.6 D.± 6解析:∵直線2x+3y-k=0和直線x-ky+12=0的交點在x軸上,可設交點坐標為(a,0),∴{■(2a"-" k=0"," @a+12=0"," )┤解得{■(a="-" 12"," @k="-" 24"," )┤故選A.答案:A 3.已知直線l1:ax+y-6=0與l2:x+(a-2)y+a-1=0相交于點P,若l1⊥l2,則點P的坐標為 . 解析:∵直線l1:ax+y-6=0與l2:x+(a-2)y+a-1=0相交于點P,且l1⊥l2,∴a×1+1×(a-2)=0,解得a=1,聯(lián)立方程{■(x+y"-" 6=0"," @x"-" y=0"," )┤易得x=3,y=3,∴點P的坐標為(3,3).答案:(3,3) 4.求證:不論m為何值,直線(m-1)x+(2m-1)y=m-5都通過一定點. 證明:將原方程按m的降冪排列,整理得(x+2y-1)m-(x+y-5)=0,此式對于m的任意實數(shù)值都成立,根據(jù)恒等式的要求,m的一次項系數(shù)與常數(shù)項均等于零,故有{■(x+2y"-" 1=0"," @x+y"-" 5=0"," )┤解得{■(x=9"," @y="-" 4"." )┤
圓與圓的位置關系教學設計人教A版高中數(shù)學選擇性必修第一冊
1.兩圓x2+y2-1=0和x2+y2-4x+2y-4=0的位置關系是( )A.內(nèi)切 B.相交 C.外切 D.外離解析:圓x2+y2-1=0表示以O1(0,0)點為圓心,以R1=1為半徑的圓.圓x2+y2-4x+2y-4=0表示以O2(2,-1)點為圓心,以R2=3為半徑的圓.∵|O1O2|=√5,∴R2-R1<|O1O2|<R2+R1,∴圓x2+y2-1=0和圓x2+y2-4x+2y-4=0相交.答案:B2.圓C1:x2+y2-12x-2y-13=0和圓C2:x2+y2+12x+16y-25=0的公共弦所在的直線方程是 . 解析:兩圓的方程相減得公共弦所在的直線方程為4x+3y-2=0.答案:4x+3y-2=03.半徑為6的圓與x軸相切,且與圓x2+(y-3)2=1內(nèi)切,則此圓的方程為( )A.(x-4)2+(y-6)2=16 B.(x±4)2+(y-6)2=16C.(x-4)2+(y-6)2=36 D.(x±4)2+(y-6)2=36解析:設所求圓心坐標為(a,b),則|b|=6.由題意,得a2+(b-3)2=(6-1)2=25.若b=6,則a=±4;若b=-6,則a無解.故所求圓方程為(x±4)2+(y-6)2=36.答案:D4.若圓C1:x2+y2=4與圓C2:x2+y2-2ax+a2-1=0內(nèi)切,則a等于 . 解析:圓C1的圓心C1(0,0),半徑r1=2.圓C2可化為(x-a)2+y2=1,即圓心C2(a,0),半徑r2=1,若兩圓內(nèi)切,需|C1C2|=√(a^2+0^2 )=2-1=1.解得a=±1. 答案:±1 5. 已知兩個圓C1:x2+y2=4,C2:x2+y2-2x-4y+4=0,直線l:x+2y=0,求經(jīng)過C1和C2的交點且和l相切的圓的方程.解:設所求圓的方程為x2+y2+4-2x-4y+λ(x2+y2-4)=0,即(1+λ)x2+(1+λ)y2-2x-4y+4(1-λ)=0.所以圓心為 1/(1+λ),2/(1+λ) ,半徑為1/2 √((("-" 2)/(1+λ)) ^2+(("-" 4)/(1+λ)) ^2 "-" 16((1"-" λ)/(1+λ))),即|1/(1+λ)+4/(1+λ)|/√5=1/2 √((4+16"-" 16"(" 1"-" λ^2 ")" )/("(" 1+λ")" ^2 )).解得λ=±1,舍去λ=-1,圓x2+y2=4顯然不符合題意,故所求圓的方程為x2+y2-x-2y=0.
直線與圓的位置關系教學設計人教A版高中數(shù)學選擇性必修第一冊
切線方程的求法1.求過圓上一點P(x0,y0)的圓的切線方程:先求切點與圓心連線的斜率k,則由垂直關系,切線斜率為-1/k,由點斜式方程可求得切線方程.若k=0或斜率不存在,則由圖形可直接得切線方程為y=b或x=a.2.求過圓外一點P(x0,y0)的圓的切線時,常用幾何方法求解設切線方程為y-y0=k(x-x0),即kx-y-kx0+y0=0,由圓心到直線的距離等于半徑,可求得k,進而切線方程即可求出.但要注意,此時的切線有兩條,若求出的k值只有一個時,則另一條切線的斜率一定不存在,可通過數(shù)形結合求出.例3 求直線l:3x+y-6=0被圓C:x2+y2-2y-4=0截得的弦長.思路分析:解法一求出直線與圓的交點坐標,解法二利用弦長公式,解法三利用幾何法作出直角三角形,三種解法都可求得弦長.解法一由{■(3x+y"-" 6=0"," @x^2+y^2 "-" 2y"-" 4=0"," )┤得交點A(1,3),B(2,0),故弦AB的長為|AB|=√("(" 2"-" 1")" ^2+"(" 0"-" 3")" ^2 )=√10.解法二由{■(3x+y"-" 6=0"," @x^2+y^2 "-" 2y"-" 4=0"," )┤消去y,得x2-3x+2=0.設兩交點A,B的坐標分別為A(x1,y1),B(x2,y2),則由根與系數(shù)的關系,得x1+x2=3,x1·x2=2.∴|AB|=√("(" x_2 "-" x_1 ")" ^2+"(" y_2 "-" y_1 ")" ^2 )=√(10"[(" x_1+x_2 ")" ^2 "-" 4x_1 x_2 "]" ┴" " )=√(10×"(" 3^2 "-" 4×2")" )=√10,即弦AB的長為√10.解法三圓C:x2+y2-2y-4=0可化為x2+(y-1)2=5,其圓心坐標(0,1),半徑r=√5,點(0,1)到直線l的距離為d=("|" 3×0+1"-" 6"|" )/√(3^2+1^2 )=√10/2,所以半弦長為("|" AB"|" )/2=√(r^2 "-" d^2 )=√("(" √5 ")" ^2 "-" (√10/2) ^2 )=√10/2,所以弦長|AB|=√10.
直線的兩點式方程教學設計人教A版高中數(shù)學選擇性必修第一冊
解析：①過原點時，直線方程為y＝－34x.②直線不過原點時，可設其方程為xa＋ya＝1，∴4a＋－3a＝1，∴a＝1.∴直線方程為x＋y－1＝0.所以這樣的直線有2條，選B.答案：B4.若點P(3,m)在過點A(2,-1),B(-3,4)的直線上,則m= . 解析:由兩點式方程得,過A,B兩點的直線方程為(y"-(-" 1")" )/(4"-(-" 1")" )=(x"-" 2)/("-" 3"-" 2),即x+y-1=0.又點P(3,m)在直線AB上,所以3+m-1=0,得m=-2.答案:-2 5.直線ax+by=1(ab≠0)與兩坐標軸圍成的三角形的面積是 . 解析:直線在兩坐標軸上的截距分別為1/a 與 1/b,所以直線與坐標軸圍成的三角形面積為1/(2"|" ab"|" ).答案:1/(2"|" ab"|" )6.已知三角形的三個頂點A(0,4)，B(－2,6)，C(－8,0)．(1)求三角形三邊所在直線的方程；(2)求AC邊上的垂直平分線的方程．解析(1)直線AB的方程為y－46－4＝x－0－2－0，整理得x＋y－4＝0；直線BC的方程為y－06－0＝x＋8－2＋8，整理得x－y＋8＝0；由截距式可知，直線AC的方程為x－8＋y4＝1，整理得x－2y＋8＝0.(2)線段AC的中點為D(－4,2)，直線AC的斜率為12，則AC邊上的垂直平分線的斜率為－2，所以AC邊的垂直平分線的方程為y－2＝－2(x＋4)，整理得2x＋y＋6＝0.
空間向量基本定理教學設計人教A版高中數(shù)學選擇性必修第一冊
反思感悟用基底表示空間向量的解題策略1.空間中,任一向量都可以用一個基底表示,且只要基底確定,則表示形式是唯一的.2.用基底表示空間向量時,一般要結合圖形,運用向量加法、減法的平行四邊形法則、三角形法則,以及數(shù)乘向量的運算法則,逐步向基向量過渡,直至全部用基向量表示.3.在空間幾何體中選擇基底時,通常選取公共起點最集中的向量或關系最明確的向量作為基底,例如,在正方體、長方體、平行六面體、四面體中,一般選用從同一頂點出發(fā)的三條棱所對應的向量作為基底.例2.在棱長為2的正方體ABCD-A1B1C1D1中,E,F分別是DD1,BD的中點,點G在棱CD上,且CG=1/3 CD(1)證明:EF⊥B1C;(2)求EF與C1G所成角的余弦值.思路分析選擇一個空間基底,將(EF) ?,(B_1 C) ?,(C_1 G) ?用基向量表示.(1)證明(EF) ?·(B_1 C) ?=0即可;(2)求(EF) ?與(C_1 G) ?夾角的余弦值即可.(1)證明:設(DA) ?=i,(DC) ?=j,(DD_1 ) ?=k,則{i,j,k}構成空間的一個正交基底.
圓的標準方程教學設計人教A版高中數(shù)學選擇性必修第一冊
(1)幾何法它是利用圖形的幾何性質(zhì),如圓的性質(zhì)等,直接求出圓的圓心和半徑,代入圓的標準方程,從而得到圓的標準方程.(2)待定系數(shù)法由三個獨立條件得到三個方程,解方程組以得到圓的標準方程中三個參數(shù),從而確定圓的標準方程.它是求圓的方程最常用的方法,一般步驟是:①設——設所求圓的方程為(x-a)2+(y-b)2=r2;②列——由已知條件,建立關于a,b,r的方程組;③解——解方程組,求出a,b,r;④代——將a,b,r代入所設方程,得所求圓的方程.跟蹤訓練1．已知△ABC的三個頂點坐標分別為A(0,5)，B(1，－2)，C(－3，－4)，求該三角形的外接圓的方程．[解] 法一：設所求圓的標準方程為(x－a)2＋(y－b)2＝r2.因為A(0,5)，B(1,－2)，C(－3,－4)都在圓上，所以它們的坐標都滿足圓的標準方程，于是有?0－a?2＋?5－b?2＝r2，?1－a?2＋?－2－b?2＝r2，?－3－a?2＋?－4－b?2＝r2.解得a＝－3，b＝1，r＝5.故所求圓的標準方程是(x＋3)2＋(y－1)2＝25.
直線的點斜式方程教學設計人教A版高中數(shù)學選擇性必修第一冊
【答案】B [由直線方程知直線斜率為3，令x＝0可得在y軸上的截距為y＝－3.故選B.]3．已知直線l1過點P(2,1)且與直線l2：y＝x＋1垂直，則l1的點斜式方程為________．【答案】y－1＝－(x－2) [直線l2的斜率k2＝1，故l1的斜率為－1，所以l1的點斜式方程為y－1＝－(x－2)．]4．已知兩條直線y＝ax－2和y＝(2－a)x＋1互相平行，則a＝________. 【答案】1 [由題意得a＝2－a，解得a＝1.]5.無論k取何值,直線y-2=k(x+1)所過的定點是 . 【答案】(-1,2)6．直線l經(jīng)過點P(3,4)，它的傾斜角是直線y＝3x＋3的傾斜角的2倍，求直線l的點斜式方程．【答案】直線y＝3x＋3的斜率k＝3，則其傾斜角α＝60°，所以直線l的傾斜角為120°.以直線l的斜率為k′＝tan 120°＝－3.所以直線l的點斜式方程為y－4＝－3(x－3)．
新人教版高中英語必修3Unit 1 Festivals and Celebrations-Reading for Writing教學設計一
The topic of this part is “Write about your festival experience”.During the Listening and Speaking and Talking, students are just asked to say out their festival experiences such as the Spring Festival, Mid-autumn Day, but this part students will be asked to write down their own festival experiences. During the reading part, it introduces the Naadam Festival in Inner Mongolia Autonomous Region, which can give students a good example to imitate. Students not only learn the festival, but touch and feel the Inner Mongolian’s character, the spirit and cultural atmosphere, which can help students form the cultural awareness and learn to enjoy and value the diversity of Chinese culture.Concretely, the dairy tells the experience that the author spent the Naadam Festival in Inner Mongolia Autonomous Region with his/her friend. The structure is clear. In the opening paragraph, it introduces the topic of the Naadam Festival and the whole feeling. Then it introduces the items of the festival like the ceremony, wrestling and horse racing. Finally, it summarizes this experience. Because this part is a travel journal, we must guide students pay more attention to these details: 1. use the first person. 2. use the past tense to tell the past thing and use the present or future tense to describe the scenery. 3. use the timeline to tell the development. 4. be careful for the author’s psychology, emotion and feeling, etc.1. Read quickly to get main idea; read carefully to get the detailed information about Naadam Festival.2. Learn the structure of the reading article and language.3. Write an article about a festival experience4. Learn to use the psychology, emotions and feeling in the writing.1. Write an article about a festival experience.2. Use the structure of the reading article and language.
新人教版高中英語必修3Unit 4 Space Exploration-Listening&Speaking&Talking教學設計一
Listening and Speaking introduces the topic of “talking about how to become an astronaut”. This period is aimed to inform students some details about the requirements of being an astronaut. Students can be motivated and inspired by the astronauts. Teachers ought to encourage students to learn from them and let them aim high and dream big.Listening and Talking introduces the theme of "talk about life in space". This part also informs students more details about life in space and can inspire students to be curious about this job. 1. Guide students to listen for numbers concerning dates, years and ages etc2. Cultivate students' ability to talk about how to become an astronaut and life in space ; 3. Instruct students to use functional sentences of the dialogue such as “ first of all, I am not sure, so what might be .. I guess.. I wonder…I am curious…)appropriately.1. Guide students to understand the content of listening texts in terms of the whole and key details; 2. Cultivate students' ability to guess the meaning of words in listening; discuss with their peers how to become a qualified astronaut and describe the life in space.Part 1: Listening and SpeakingStep 1: Lead inPredictionThe teacher can ask students to predict what the listening text is about by looking at the pictures.About how to become an astronaut./the requirements of an astronautStep 2: Then, play the radio which is about an interview a. And after finishing listening for the first time, the students need to solve the following tasks.
新人教版高中英語必修3Unit 4 Space Exploration-Reading and Thinking教學設計一
Q4: What is the function of the International exploration ?Having astronauts from different countries on boardQ5: What can you learn from Para 4 ?China has made great achievements in exploring spaceQ6: What is the attitude to the space exploration ?SupportiveStep 6 Post reading---RetellPeople have always wanted to learn more about space. Before the mid-20th century, most people felt (1)_________ (travel) into space was an impossible dream. However, (2)____ the help of scientists, peoplesucceeded in realizing their dream (3) _________ (explore) space. On 4 October 1957, the Sputnik 1 satellite (4) ____________(launch) by the USSR. (5) ________________ scientists try to make sure nothing goes wrong, accidents can still happen. These disasters made everyone(6)___________(disappoint), but people still believe in the importance of (7) ________(carry) on space exploration. In 2003, China became the third country to (8)_____________ (independent) send humans into space. Then Shenzhou 6 and 7 completed (9)____ second manned orbit and the first Chinese spacewalk. In spite of the difficulties, scientists hope future (10)__________ (discovery) will not only enable us to understand the universe but also help us survive well into the future.Answers: 1. travelling 2. with 3. to explore 4. was launched 5. Although6. disappointed 7. carrying 8. independently 9. a 10. discoveriesStep 6 Post reading---Critical thinkingQ1: What do you think of the space exploration ? I think it is beneficial to us. Through further study of space, people will make full use of it in the future, such as the space experiments by Wang Yaping in Tian Gong 1.Q2: If you are determined to be an astronaut, what should you prepare at present ?First of all, I should study hard to get a related college degree. Besides, I must keep mental and physical healthy.Step 7. HomeworkTry to summarize the structure of the article by a mind map.
新人教版高中英語必修3Unit 4 Space Exploration-Reading For Writing教學設計一
另一方面，其余的人反對這個計劃，因為它可能會導致一些不好的影響。7.I hold the belief that space exploration not only enable us to understand how the universe began but also help us survived well into the future.我堅信探索太空不僅能夠使我們了解宇宙的起源而且能夠幫助我們更好地走進未來。8.I think we should spend more time and money exploring space so as to provide new and better solutions to people's shortterm and longterm problems.為了給人類的短期和長期問題提供更新和更好的解決方法，我認為我們應該花更多的時間和金錢來探索太空。9．From my point of view，it is wrong of young people to depend on their telephones too much，which may do harm to both their physical and mental health.在我看來，年輕人過度依賴手機是不對的，因為它們可能會對他們的身心健康都有害。最近你班同學就“人類是否應該進行宇宙探索”這個問題進行了激烈的討論。有人認為，探索宇宙不僅讓人類更好地了解宇宙的發(fā)展，還可以用來指導農(nóng)業(yè)生產(chǎn)，以及把一些探索太空的高新技術用于現(xiàn)實生活；也有一些人認為探索太空花掉了大量的人力物力；影響了人們的生活水平。請你根據(jù)以下情況寫一篇報告并發(fā)表自己的觀點。注意：1.寫作內(nèi)容應包括以上全部要點，可適當發(fā)揮，使上下文連貫；
新人教版高中英語必修3Unit 5 The Value of Money-Reading and Thinking教學設計一
Everybody wants to get wealth.In today’s material world,making money or becoming wealthy symbolizes a person’s success and capability. Many people just make every effort, pay any price to attain greater wealth. With money,they can buy nice, large apartments in nice neighborhood. With money they can own luxurious cars. Wealth seems to bring all happiness in life.But is wealth the only road to happiness? Not really. There are many things in the world, which are beyond the means of money, such as friendship, love, health and knowledge. People are so preoccupied with struggling for money that they have no time or would not take the time to form or maintain friendship. What happiness can they feel living as lonely miserable creatures without love or friends in the world even if they accumulate tremendous wealth?In my opinion, people can’t do anything without money, but money is not everything. What money will bring you depends on your personal belief and goal in life. If you are kind enough to help others, especially the poor, money is a good thing to you. With it, you can do much more for the benefit of people and your country, and it will add to your own happiness. If you want money just for your own needs, you’ll never be satisfied or happy. In a word,you should have money spent for more people. Only then can money be the source of your happiness.Step 8 Homework4 students in a group, one acts Roderick, one Oliver, one servant and the fourth one acts Henry Adams, then listen to the tape, pay more attention to the difference between American English and British English in pronunciation, stress, tone.
新人教版高中英語必修3Unit 5 the value of money-Reading For Writing教學設計一
【參考范文】Narrator：(Henry is smiling as he leaves the restaurant. As he is walking down the street, he sees a sign for a place that cuts hair. He decides to get it cut. )H＝Henry；B＝Barber；R＝rude manH：Good afternoon, I'd like to get a cut, if I may. (The barber looks at Henry's hair and continues cutting another man's hair. )Er, I'd really like a haircut. As you can see it's much too long. B：(in a rude manner) Yes, I can see that. Indeed, I can. H：Fine, well I'll have a seat then. (He sits in one of the barber's chairs. The barber turns to look at Henry. )B：It's quite expensive here, you know！Are you sure you can afford it?H：Yes. I think so. (In comes the rude man. )R：Hey you there. I need a haircut quickly. Can you do me straightaway?B：All right, then, get in the chair and I'll see what I can do. R：Thank you. (sits down in one of the barber's chairs)H：Excuse me, but I was here first. Aren't you going to do my hair first?B：This man's in a hurry. H：Well so am I！I insist that you cut my hair first. B：OK, but I'll have to be quick. This gentleman is waiting. H：Thank you. (They both become quiet. After his hair is cut, the barber tells Henry how much he must pay. Henry shows the barber the bank note. )B：Why, Mr . . . (looks shocked)H：Adams. Henry Adams. I'm sorry, I don't have any change. R：You're that Mr Adams! Well，I'm glad I waited or I might never have known it was you. B：Why, Mr Adams, please don't worry！(wearing a big smile) Nothing to worry about！Nothing at all!Please come back any time, even if you only need too little hairs cut！It will be my honour to serve you!
